Matematika Sekolah Menengah Atas Diketahui : f(x) = x – 3 g(x) = 2x2 – 6xb(x) = x2 – 9m(x) = 2x2 – x – 15 (g(x))/(b(x)) = … . A. (2x(x-3x))/((x+3)) B. (2x(x-3))/((x+3)) C. 2x/((x-3)) D. 2/((x+3)) E. 2x/((x+3))​

jeffryratkeulv – April 11, 2023

Diketahui :

f(x) = x – 3

g(x) = 2x2 – 6x

b(x) = x2 – 9

m(x) = 2x2 – x – 15



(g(x))/(b(x)) = … .

A. (2x(x-3x))/((x+3))

B. (2x(x-3))/((x+3))

C. 2x/((x-3))

D. 2/((x+3))

E. 2x/((x+3))

​

Penjelasan dengan langkah-langkah:

g(x) = 2x² - 6x

b(x) = x² - 9

[tex] \: [/tex]

[tex] = \frac{g(x)}{b(x)} [/tex]

[tex] \: = \frac{2 {x}^{2} - 6x}{ {x}^{2} - 9 } [/tex]

[tex] = \frac{2x \cancel{(x - 3)}}{ \cancel{(x - 3)}(x + 3)} [/tex]

[tex] = \frac{2x}{x + 3} [/tex]

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